![]() ![]() In the hits from that search, there will be a number of websites that will help you figure out the answer. Notice that I completely ignore capitals in the formulas. The search suggestion is to type the reactants plus an arrow, like this: Note how easy it was to balance the copper half-reaction. No need to equalize electrons since it turns out that, in the course of balancing the half-reactions, the electrons are equal in amount. The answer to 2b is the exact same as 2a in terms of the stoichiometry of the reaction.Įxample #3: MnO 4¯ + H 2S -> Mn 2+ + S 8ģ) Make the number of electrons equal (note that there are no common factors between 5 and 16 except 1):Ĥ0H 2S -> 5S 8 + 80H + + 80e¯ 16Mn 2+ + 64H 2O 5S 8 + 16Mn 2+ + 64H 2OĪnother possibility of removing a factor of 8 destroyed by an odd number, in this case, the 5 in front of the S 8. Notice that, in the answer, the S coefficient stays the same (but the subscript of 8 goes away) and the other coefficients are all reduced by a factor of 8. Also, note that duplicates of 48 electrons and 48 hydrogen ions were removed.ĥ) Sometimes, you will see the nitric acid in molecular form:Ģ4H 2S + 16HNO 3 -> 3S 8 + 16NO + 32H 2OĮxample #2b: H 2S + HNO 3 -> NO + S + H 2Oĭiscussion: Many times, teachers and textbooks will use S rather than S 8. The duplicates are 6e¯, 3H 2O, and 6H +Ģ4H 2S -> 3S 8 + 48H + + 48e¯ 16NO + 32H 2O 3S 8 + 16NO + 32H 2OĬomment: removing a factor of 8 does look tempting, doesn't it? However, the three in front of the S 8 (or the five in the next example) makes it impossible. Note that items duplicated on each side were cancelled out. These items are usually the electrons, water and hydrogen ion.Īfter Example #5c, I have a suggestion for searching for help on balancing a specific equation.Įxample #1: ClO 3¯ + SO 2 -> SO 4 2¯ + Cl¯ĦH 2O + 3SO 2 -> 3SO 4 2¯ + 12H + + 6e¯ 3SO 4 2¯ + Cl¯ + 6H + In order to get the electrons in each half-reaction equal, one or both of the balanced half-reactions will be multiplied by a factor.Ģ) Duplicate items are always removed. ![]()
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